Consider the following "multiplication" over "addition":
$$
a \times (b + c)
$$
The distributive law in common notion is the left distributive law:
$$
a \times (b + c) = a \times b + a \times c
$$
But what if?:
$$
a \times (b + c) = b \times a + c \times a
$$
$$
a \times (b + c) = a \times b + c \times a
$$
$$
a \times (b + c) = b \times a + a \times c
$$
Are there any name for these? I guess they're "anti", "exo", and "endo" distributive, respectively.
Are there any notable algebraic structure with any of these laws?
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9I know this isn't what you're looking for, but any abelian structure that has a distributive law will also satisfy these distributive laws. – Carl Schildkraut Oct 14 '18 at 07:54
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Ad hoc, I'd call them skew-distributivity. – Wlod AA Oct 03 '19 at 03:25
1 Answers
My comment was a bit wrong, and too brief, so I'm going to expand this into a partial answer.
Suppose you have a set $R$ with operations $+$ and $\times$ such that $(R, +)$ is a group, and $\times$ left-endodistributes over $+$. Let $0$ be the identity under $+$.
Fix $a, b \in R$. Then $$a \times 0 = a \times (0 + 0) = 0 \times a + a \times 0 \implies 0 \times a = 0.$$ We also have $$0 = 0 \times (a + 0) = a \times 0 + 0 \times 0 = a \times 0,$$ and $$a \times b = a \times (b + 0) = b \times a + a \times 0 = b \times a.$$
Therefore, $\times$ is commutative, and therefore distributes over $+$.
The same can be done with left-exodistributivity.
For left-antidistributivity, consider first $$0 \times 0 = 0 \times (0 + 0) = 0 \times 0 + 0 \times 0 \implies 0 \times 0 = 0.$$ Next, note that $$0 \times a = 0 \times (a + 0) = a \times 0 + 0 \times 0 = a \times 0.$$ Then, $$(0 + a) \times (0 + a) = (0 + a) \times 0 + (0 + a) \times a = 0 \times 0 + 0 \times a + a \times 0 + a \times a,$$ which, when combined with the above identity, simplifies to $0 \times a + 0 \times a = 0$. But then, $$0 = 0 \times a + 0 \times a = a \times (0 + 0) = a \times 0 = 0 \times a.$$ Finally, this again gives us that $\times$ is commutative and distributes over $+$, as $$a \times (b + 0) = b \times a + 0 \times a = b \times a.$$
While this doesn't mean that left anti/endo/exo-distributivity properties are of no interest, it does mean that, in order to avoid "trivial" examples (i.e. ones where $\times$ distributes), we have to sacrifice a fair amount of structure of the additive magma, which means the result is not going to be as "ring-like" as you might have hoped.
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