$\;x^{52}=x^{-4}\cdot r^7\;$ what will be the value of r?

Question

If $x^{52}=x^{-4}\cdot r^7$ then what will be the value of $r$?

Please fix your math notation. Currently it's incomprehensible. Are you using MathJax? — Matti P., Oct 23 '18 at 06:32
Since $x^{-4}$ couldn't make sense if $x=0$ we can safely assume that $x\neq 0$. Multiply both sides by $x^4$ then to arrive at the equality $x^{56}=r^7$. Continue. — JMoravitz, Oct 23 '18 at 06:39

score 1 · Answer 1 · answered Oct 23 '18 at 06:38

1

Multiplying by $$x^4\neq 0$$ we get $$x^{56}=r^7$$ so $$r=\sqrt[7]{x^{56}}$$

answered Oct 23 '18 at 06:38

1 Answers1