Is there a Totally Ordered Set which the only order-isomorphism to itself is the Identity? And the set and its inverse are not well ordered

Asked Nov 04 '18 at 18:05

Active Nov 04 '18 at 19:06

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the inverse set of $\ \left(A,<\right) $ is $\ \left(A,<^{-1}\right) $ with $\ a<^{-1}b\iff b<a$

the set and its inverse are not well ordered

edited Nov 04 '18 at 19:06

Asaf Karagila

393,674

asked Nov 04 '18 at 18:05

Kofiko

29

You've edited the question like you've not read the duplicate one. – Asaf Karagila Nov 04 '18 at 19:04

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