I'm thinking of this problem in 2 ways.
There's 5 trees, each the same width $X$. This leaves 4 inner "gaps" of $20$ meters in length? So, my answer would be $(20 \times 4) + (5\times X)$ or rather $80 + 5x$
If there's 2 trees, from each end including the inner gap is $20$ meters. If there's 3 trees, then it from tree one to tree three would be $40$ meters. Going by this 4 trees would be $60$ meters, and 5 trees would be $80$ meters. Not sure what this would be in the form of an equation.
Thoughts on what is more valid? And any tips regarding how to interpret similar questions?