I can not understand the solution.How does the second step come about? How does the expression in brackets appear?
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$ab + ac = a[b+c]$ :-) – trancelocation Nov 20 '18 at 08:16
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yeah, I know, but here it is somehow not obvious to me – Alexander Nikolin Nov 20 '18 at 08:20
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Take note:
$$(n - k + 1)! = (n-k)! \cdot (n - k + 1)$$
$$k! = (k-1)! \cdot k$$
Rewrite the expression after the first equal sign with this in mind: you should see a common factor you can neatly factor out.
PrincessEev
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thanks! the problem was that the first property was not clear to me – Alexander Nikolin Nov 20 '18 at 08:25