I have a module homomorphism $p:M\rightarrow M$. I would like to find another module homomorphism $\phi:M\rightarrow \ker(p)$. Finding such a thing seems to be very challenging however. Is this possible? Note also that $p^2=p$.
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Let $\phi=1_M-p$. Then $p\circ \phi=p(1_M-p)=p-p^2=p-p=0$, so $\phi:M\to\ker p$. But there are many such maps $\phi$; taking $\phi$ to be the $0$ map would also define a map from $M$ to $\ker p$.
Ashwin Trisal
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Ah, I see what I'm missing. I need the map to be surjective as well. – gradintherockies Nov 25 '18 at 20:25