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Let
θ=54
5θ=270
2θ+3θ=270
2θ=270-3θ
sin(2θ)=sin(270-3θ)
sin(2θ)= -cos(3θ)
From where does -ve sign come from?

270-3θ will be in 2quad where sin is +ve.

Fareed
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2 Answers2

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\begin{align} \sin (270^\circ-\alpha) &= \sin(270^\circ)\cos(\alpha) -\cos(270^\circ) \sin(\alpha) \\ &=- \cos (\alpha) \end{align}

Siong Thye Goh
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$\sin(-90^\circ -\alpha) = \cos(\alpha)$ for any $\alpha$