how to prove Bayes theorem? (Develop from conditional probability ) 2 criterias -Total of law is probability -multiplication rule Can someone show me the mathematical proof & steps for this please?
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1There's a perfectly good proof on Wikipedia. Are there steps there that you don't follow and would like more explanation on? – Nick Peterson Dec 05 '18 at 16:16
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1There isn't much to prove at all... – Federico Dec 05 '18 at 16:17
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The conditional probability is defined as $$ P(A|B) = \frac{P(A\cap B)}{P(B)}, $$ hence $$ P(A|B) P(B) = P(B|A) P(A) . $$
Federico
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Hints
- Write $P(A \cap B)$ two different ways using conditional probability
- these are therefore equal by Euclid's first axiom
- manipulate into Bayes' theorem (assuming none of the probabilities are $0$)
Henry
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