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In the image given in the link, the square of the hypotenuse is 2ab. But it can't be true. I can't be true. I can't seem to find the reason. any help would be appreciated.

Nasir Aziz
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  • Is that figure meant to be a square? If so...the diagonals of a square are equal so we'd need $a=b$. If it's not meant to be a square then the area of the figure is not $c^2$. – lulu Dec 08 '18 at 19:17

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Since you talk about hypotenuse, it means that the diagonals of the quadrilateral are perpendicular. Using $$c^2=a^2+b^2$$ and $$c^2=2ab$$ you get $$a^2+b^2-2ab=0$$ or $$(a-b)^2=0$$This is valid for $a=b$

Andrei
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