Is every real valued continuous function on $(0,1)$ is uniformly continuous?

Question

Is every real valued continuous function on the interval $(0,1)$ is uniformly continuous?

I think the answer is no, and to reject the statement, we need to come up a continuous function probably $f(x)=\frac{1}{x}$ and follow the following link:

Coming up with an example, a function that is continuous but not uniformly continuous

But it does not work because $\delta=\min(x,1)$ cannot be applied because $x$ cannot attain $1$.

Possible duplicate of Coming up with an example, a function that is continuous but not uniformly continuous — Boshu, Dec 09 '18 at 06:20
Take a good look at the proof, and the definition of uniform continuity; just because you cannot copy a proof word for word does not mean that it does not hold. You need to understand what cause $\frac{1}{x}$ to be not uniformly continuous, and whether changing the right hand side of the interval actually affects it. — Boshu, Dec 09 '18 at 06:52
@Boshu: Sorry I cannot understand, that's why I asked. Could you clarify it for me? — Saeed, Dec 09 '18 at 06:57

score -1 · Answer 1 · answered Dec 09 '18 at 07:08

The link I provided above is fairly comprehensive. What I think will help you is understanding uniform continuity better.

Uniform continuity means that if two points are within some fixed distance of each other, the values taken at those points can only be so far apart. However, because $\dfrac{1}{x}$ goes to infinity within that small interval, it means that the difference between the values taken by a function at two points at some distance, gets larger as we move closer to $0$. Consequently, $\dfrac{1}{x}$ is not uniformly continuous. You can now attempt to formally write this down following from the answer I've linked above.

Is every real valued continuous function on $(0,1)$ is uniformly continuous?

1 Answers1