We have the following the min cost network flow problem. Notice that the arcs $(1,2), (2,3), (4,2), (3,6), (5,6)$ give a feasible basis. We easily find a feasible solution:
$$ (x_{12}, x_{23}, x_{36}, x_{42}, x_{56}) = (-6,-1,-1,-3,-1) $$
where we have assumed $b_i < 0$ is supply . When trying to find dual variables, we obtain
\begin{align*} y_1-y_2 = c_{12} = 2 \\ y_2-y_3 = c_{23} = 3 \\ y_4-y_2 = c_{42} = 5 \\ y_3-y_6= c_{36} = 3 \\ y_5-y_6 = c_{56} = 7 \\ \end{align*}
My question is, in solving this system, can we assume $y_1$ or $y_5$ to be $0$ since we can for a root node from them?
