Find the Cartesian form of the parametric equations: $x=2\sin^2(\theta)$, $y=7\cos^2(\theta)$

Question

I am trying to find the cartesian form of the parametric expressions $x=2\sin^2(\theta)$, $y=7\cos^2(\theta)$. I have $x=2-cos^2(\theta)$ but i can't work it after that.

score 0 · Answer 1 · answered Dec 10 '18 at 21:48

0

$$sin^2(\theta)+cos^2(\theta)=1$$ $$\frac{x}{2}+\frac{y}{7}=1$$

answered Dec 10 '18 at 21:48

mmcrjx

654

1

Also with the restrictions $x, y \ge 0$ (which also implies $x \le 2$, $y \le 7$). – Daniel Schepler Dec 10 '18 at 22:04
Yeah.. Thanks :) – mmcrjx Dec 10 '18 at 22:06

Find the Cartesian form of the parametric equations: $x=2\sin^2(\theta)$, $y=7\cos^2(\theta)$

1 Answers1