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If two players A and B throw a pair of dice. A will win if he gets a sum of 7 and B will win if he gets a sum of 5. If A starts the game what is the probability that 3 will appear on one of the die in the last throw

J RAVINDRANATH
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    Hi! What have you already done to solve this problem? If you tell us what exactly you don't understand about the problem, we can help you then. – Vasily Mitch Dec 17 '18 at 17:00
  • I am getting confused how to consider the conditional probability in this case – J RAVINDRANATH Dec 17 '18 at 17:12
  • Do A and B each throw once, or do they alternate until one wins? – eyeballfrog Dec 17 '18 at 18:21
  • @JRAVINDRANATH Conflict here. On the one hand you haven't shown any work. On the other hand, cond. probability problems are tricky. I will give subsequent comment that provides outline of solution. Ask that you try for 24 hours and then if needed, show your work, editing your question. – user2661923 Dec 17 '18 at 19:35
  • @JRAVINDRANATH You need to calculate 4 variables: a = chance that 1st player wins, b = chance that 2nd player wins [which is = to (1-a)], c = chance that 3 appears on last throw if 1st player wins, d = chance that 3 appears on last throw if 2nd player wins. Then, answer is ac + bd. – user2661923 Dec 17 '18 at 19:38
  • P(A)=12/17, P(B) = 5/17, P(C) and P(D) I am unable to get it – J RAVINDRANATH Dec 17 '18 at 23:26
  • @JRAVINDRANATH assume the last throw is a 7. how many different ways can 7 appear as the sum of the two dice? how many of those ways involve a 3 appearing on one of the two dice? – user2661923 Dec 18 '18 at 00:52
  • P(C)=2/6 and P(D)=2/4 – J RAVINDRANATH Dec 18 '18 at 11:45
  • If it is ac+bd = 4/17+5/34 = 13/34 but the answer given is 11/28 – J RAVINDRANATH Dec 18 '18 at 11:50

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