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If

  • "A" denotes "divided by"
  • "B" denotes "added to"
  • "X" denotes "subtracted from"
  • "R" denotes "multiplied by"

then $$18R12A4X8B6\;=\;\text{?}$$

$\left(A\right)50 \quad\left(B\right)102 \quad \left(C\right)45 \quad \left(D\right)32$

My Approach $\Longrightarrow$ I tried it in two ways

First approach: $$18\times\left[\left(8+6\right)-\left(12\div4\right)\right]=198$$

Second approach: $$18\times12\div4-8+6=40$$

Blue
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Mohan Sharma
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    For example 6X4 would be 4-6 not 6-4, since x is "subtracted from". – coffeemath Dec 19 '18 at 06:26
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    What were your instructions? Were you expected to do this from left to right? If not what were the rules. The answer can be anything you want depending on what rules you were given. – fleablood Dec 19 '18 at 06:28
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    Okay I'd do it, with coffemaths obeservation, as $18R12 = 18*12 = 216$. $216A4 = 216\div 4 = 54$. And $54X8=8 -54 = -46$. And $-46B6 = -46+6 = -40$. I don't like to ever call a question a stupid question but for this I'll make an exception. – fleablood Dec 19 '18 at 06:35
  • @fleablood the question is from math magician compition.no more instructions are given .I have provided everything I know – Mohan Sharma Dec 19 '18 at 06:40
  • @fleablood I agree – Mohan Sharma Dec 19 '18 at 06:42
  • @fleablood one thing that troubles me more is that why I am not getting even a wrong answer from the given options – Mohan Sharma Dec 19 '18 at 06:44
  • It depends on the order of operations. If you do it by the standard arithmetic model this is $(8+6) -18\times \frac {12}4$. If you do this in strict left to right the answer is $-40$. Obviously you aren't supposed to do either (else why the idiocy of replacing the symbols) but it's ambiguous as to what order the intuitively expect. You can try them in different order until you get something but life's too short to waste on stupid activities and the people who asked this don't deserve your attention. – fleablood Dec 19 '18 at 06:51

1 Answers1

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18*12/4-8+6 =18*3-8+6 =54-8+6 =44+6 =50 Correct option is A

Mayur Singh
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