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Are there any examples where the inductive step works but the base case does not? I know there are some where the latter is more difficult.

J. Dionisio
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    Try "proving" that $\sum_{i=1}^n i = n(n+1)/2 + 1000$. – PhoemueX Dec 21 '18 at 16:48
  • Look up the inductive 'proof' that all horses are the same color. Basically, it is 'proving' that for any set of $n\ge2$ objects: any two objects from that set are the same color. The step works, but the base fails. – Bram28 Dec 21 '18 at 20:58

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