This is to convert my comment to an answer. First of all, the set of planar isometries forms a group $Isom(E^2)$, being a group means that the composition of isometries (product in a group) is again an isometry and the inverse of an isometry is again an isometry. This group sits inside of a larger group, the group of Euclidean similarities, $Sim(E^2)$ consisting of compositions of Euclidean isometries and dilations. Two elements $g_1, g_2$ of a group $G$ are called conjugate if there is a third element $h\in G$ such that $g_2= h g_1 h^{-1}$. This conjugation operation should be similar for linear algebra when you diagonalize square matrices $A$ by replacing them with conjugate matrices $D=PAP^{-1}$. From the viewpoint of coordinates, conjugating one isometry of $E^2$ by an element of $Sim(E^2)$ amounts to changing one Cartesian coordinate system with another Cartesian coordinate system (the center of coordinates is likely to change as well).
Now, let's see what conjugation does to various types of isometries of $E^2$: The conjugate of a rotation $R_{\phi,o}$ by the angle $\phi$ and center $o$ after conjugation becomes a rotation $R_{\pm\phi,o'}$ with the new center. (The angle of the rotation changes to its opposite if you conjugate by an orientation-reversing transformation.) The conjugate of a translation $T_{L,D}$ along an oriented line $L$ by the distance $D\ge 0$ is still a translation $T_{L',D'}$, but, in general, $D\ne D'$ (since we are allowing conjugation by similarities). It is a nice exercise to check that any (nonzero) translation can be conjugate to any other (nonzero) translation.
A reflection $S_L$ in a line $L$ is conjugate to a reflection $S_{L'}$ is another line $L'$; again, all reflections are conjugate. Lastly, for a glide-reflection $G_{L,D}$ ($D$ is the distance of translation along a line $L$ and $L$ is the line of translation and of reflection), the conjugate is another
glide-reflection $G_{L',D'}$. More specifically, if you conjugate by a Euclidean similarity $h$ with the dilation factor $\lambda$ then
$$
h G_{L,D} h^{-1} = G_{h(L),\lambda D}.
$$
As before, any two glide-reflections are conjugate. Lastly, conjugating the identity map does not change it at all:
$$
h \cdot 1 \cdot h^{-1}= 1.
$$
Another nice exercise to work out is that two linear transformations of different types are never conjugate to each other. For instance, if $g_1$ is and isometry fixing a subset $F\subset E^2$ (say, a line), then $hg_1h^{-1}$ fixes a subset $h(F)\subset E^2$. Since a reflection fixes a line and a glide reflection has no fixed points, the two are never conjugate to each other. A glide-reflection is not conjugate to a translation since one is orientation-reversing and the other preserves orientation of $E^2$.
Thus, glide-reflections constitute a class of planar isometries which is manifestly different from the other classes.