0

Here's the question

Consider a sequence of estimators $X_{i}=X_{1},X_{2},...,X_{N}$ for $i=1,...,N$. Each estimator is resulting from a sample $j=1,...,n$. For each estimator $X_{i}$ the asymptotic normality is satisfied, as $n \rightarrow \infty$ with $N(0,X_{i}^2)$ and $σ^2=X_{i}^2$. Can we say that the asymptotic normality of the sequence $X_{i}$ is satisfied?

Konstantinos Gk
  • 1
  • 1
  • "asymptotic normality is satisfactory" means "asymptotic normality is satisfied/verified" ? ALso, $\rightarrow N(0,X_{i}^2)$ makes no sense, you meant $\rightarrow N(0,\sigma_{i}^2)$ ? Also what is $X$ ? – leonbloy Jan 14 '19 at 14:57
  • Thank you for the comments. I made some changes to my question. – Konstantinos Gk Jan 22 '19 at 23:40

0 Answers0