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I am reviewing this to teach this concept this year, and I have completely forgotten how to do these questions. Am I right in the fact that it needs to be some combination of multiplication, division and indices to reach 98 using 5 and 2? My instinct was 5*2*5*2-2 but that doesn't tie in with the log laws. This is frustrating me! Help!

gt6989b
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Georgia F
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1 Answers1

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$\log_7 98 = \log_7 (7^2 \times 2) = \log_7 (7^2) + \log_7 2 \approx 2.36$

$\log_7 70 = \log_7 (7 \times 5 \times 2) = \log_7 7 + \log_7 5 + \log_7 2 \approx 1 + .83 + .36 = 2.19$

J. W. Tanner
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