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Can you find the area of a triangle if it's 2 sides are given and the angle formed by these sides are given?

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For completeness , I prove that the area equals $\frac{1}{2}ab\sin c$ .Let the sides of known measures be $AB$ and $AC$ . Let the known angle be $\angle BAC$ enter image description here

Draw perpendicular $CD$ to $AB$ . Then , the area = $$\frac{1}{2}bh=\frac{1}{2}AB\cdot CD=\frac{1}{2}AB\cdot (AC\cdot \sin \angle CAB) $$

Sinπ
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Use that $$A=\frac{1}{2}ab\sin(\gamma)$$ etc

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Yes.
$$A=\frac 12ab\sin \theta$$