Given any fractional number in any base, for example $0.5_{10} = 0.8_{16}$, pretty simple as this gives no recurring fractional numbers.
However, given $0.255_{10} = \overline{\text{4147AE}_{_{16}}}$ is a conversion that has a recurring fractional number.
$${0.255_{_{10}}\times16_{_{10}}}=0.08_{_{10}}\text{ remainder }\color{red}{\overline{\color{green}{4}}}_{_{16}}\\ {0.08_{_{10}}\times16_{_{10}}}=0.28_{_{10}}\text{ remainder }\color{red}{\overline{\color{green}{1}}}_{_{16}}\\ {0.28_{_{10}}\times16_{_{10}}}=0.48_{_{10}}\text{ remainder }\color{red}{\overline{\color{green}{4}}}_{_{16}}\\ {0.48_{_{10}}\times16_{_{10}}}=0.68_{_{10}}\text{ remainder }\color{red}{\overline{\color{green}{7}}}_{_{16}}\\ {0.68_{_{10}}\times16_{_{10}}}=0.88_{_{10}}\text{ remainder }\color{red}{\overline{\color{green}{a}}}_{_{16}}\\ {0.88_{_{10}}\times16_{_{10}}}=0.08_{_{10}}\text{ remainder }\color{red}{\overline{\color{green}{e}}}_{_{16}}$$
Is the above the correct way to display this, and if so, what would be the simplest way to explain that they need to take the remainders from the top and place them from the MSB to the LSB (Most Significant Bit, Least Significant Bit).