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Im not sure im doing this correctly but it seems that I am getting this

T(1) = 1

T(2) = T(2-1) + 3 = T(1) + 3 = 1 + 3

T(3) = T(3-1) + 3 = T(2) + 3 = 1 + 3 + 3

T(4) = T(4-1) + 3 = T(3) + 3 = 1 + 3 + 3 + 3

How do I solve this?

1 Answers1

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Use the formula $$T_n=1+(n-1)\cdot3$$