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Using this formula

$$x_{1,2}={-b\pm\sqrt{b^2-4ac} \over 2a} = \space \cdots$$

what should be the correct format of the solution if I want to put both roots (x) on one line?

Thanks in advance

Blue
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1 Answers1

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Well, for example:

$$x^2+x-1=0\space\Longleftrightarrow\space x=\frac{\pm\sqrt{5}-1}{2}\tag1$$

Or:

$$x^2+x-1=0\space\Longleftrightarrow\space x=-\frac{\sqrt{5}+1}{2}\space\vee\space x=\frac{\sqrt{5}-1}{2}\tag2$$

Jan Eerland
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