First of all you have to use the monthly interest rate $i_{12}=\frac{0.12}{12}=\frac{i}{12}=0.01$
Then you set up an equation. The compounded loan (L) minus the sum of the compounded payments (annuities) is at most zero. Without the values the inequality is
$$L\cdot (1+\frac{i}{12})^{12\cdot n}-a\cdot
\frac{(1+\frac{i}{12})^{12\cdot n}-1}{\frac{i}{12}} \normalsize
\leq 0$$
We can use the equality for calculation and then solve for n. At the end we can regard the inequality.
$$L\cdot (1+\frac{i}{12})^{12\cdot n}-a\cdot
\frac{(1+\frac{i}{12})^{12\cdot n}-1}{\frac{i}{12}}\normalsize
= 0$$
Inserting the values and bring the negative term to the RHS.
$$800\cdot 1.01^{12\cdot n}=60\cdot
\frac{1.01^{12\cdot n}-1}{0.01}$$
You can start by multiplying both sides by $0.01$
$$8\cdot 1.01^{12\cdot n}=60\cdot \left(
1.01^{12\cdot n}-1\right) = 60\cdot
1.01^{12\cdot n} -60
$$
Subtracting $8\cdot 1.01^{12\cdot n}$ and adding $60$ on both sides of the equation.
$$60=52\cdot
1.01^{12\cdot n}
$$
Can you proceed?