I am currently reading a book about fractals and the author states the result that Hausdorff measure is semifinite. Can someone tell me how to prove or provide a hint for me?
Asked
Active
Viewed 107 times
2
-
2What does "semifinite" mean? – Chris Eagle Feb 26 '13 at 15:45
-
For every measurable set A which has infinite measure,there exists a subset B of A,which has positive finite measure. – Ben Feb 26 '13 at 15:55
-
2This is not easy, and I would not want to reproduce the proof here. See Theorem 8.19 in Geometry of Sets and Measures in Euclidean Spaces by Pertti Mattila. – Feb 26 '13 at 19:54