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How to prove this?

  1. Think of a simple multiplication problem, I will use $22 \times 7$

  2. Divide the first factor by 2; if the number isn't a whole number, floor it (e. g. $11 / 2 = 5$), until you come to $1$

  3. Multiply the second factor by $2$ with increasing power ($7 \times 2^0, 7 \times 2^1$ etc.) until you make as many numbers as you made in step 1, make "columns".

  4. Remove every column that has an even number in its upper cell.

  5. Add all number in the second line together.

This works universally for whole numbers.

e. g.

$22;11;5;2;1$

$7;14;28;56;112$

this becomes

$11;5;1$

$14;28;112$

$22 \times 7 = 14 + 28 + 112 = 154$

Thanks in advance!

J. W. Tanner
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  • This has to do with binary multiplication. See for example, this answer of mine : https://math.stackexchange.com/questions/3122152/multiplying-two-numbers-using-only-the-left-shift-operator/3122180#3122180 especially the latter half on the Vakil method – Sarvesh Ravichandran Iyer Mar 21 '19 at 13:03
  • Observe $22=2+4+16$ and $7(2+4+16)=14+28+112$ – Daniel Mathias Mar 21 '19 at 13:40

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