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In a recent test I took, I received a question in an awkward form: $$\sqrt y-\sqrt[3]{1000-y}=16$$ How would I go about solving this?

  • Welcome to MSE. In the future please include in the body of the question your own thoughts, the effort made so far, and the specific difficulties that got you stuck (e.g. the comment under the answer by model_checker). – Lee David Chung Lin Mar 24 '19 at 02:55

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Let $x = \sqrt{y}$ and then you have that $$(x-16)^3 = 1000-x^2$$ which gives you a cubic that you can solve using standard methods.

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