In a recent test I took, I received a question in an awkward form: $$\sqrt y-\sqrt[3]{1000-y}=16$$ How would I go about solving this?
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Welcome to MSE. In the future please include in the body of the question your own thoughts, the effort made so far, and the specific difficulties that got you stuck (e.g. the comment under the answer by model_checker). – Lee David Chung Lin Mar 24 '19 at 02:55
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Let $x = \sqrt{y}$ and then you have that $$(x-16)^3 = 1000-x^2$$ which gives you a cubic that you can solve using standard methods.
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I have tried this, and it leads me to $x^3 - 47 x^2 + 768 x - 5096 = 0$, which according to WolframAlpha doesn't have an integer solution. – Kavi Agrawal Mar 23 '19 at 23:00
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1@KaviAgrawal: That is correct, it doesn't have an integral solution. Why do you think it should? – Ross Millikan Mar 23 '19 at 23:04
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How would I be able to derive the solution by hand, in that case? – Kavi Agrawal Mar 23 '19 at 23:06
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Newton Ralphson is one iterative method that could be used to approximate roots. – Student Mar 23 '19 at 23:07