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The slope is given by $ \frac{y1-y2}{x1-x2}$

If the slope is given we can also calculate the value of x2.

slope= $ \frac{y1-y2}{x1-x2}$

x1-x2= $\frac{y1-y2}{slope}$

x2=x1-$ \frac{y1-y2}{slope}$

Suppose a triangle we have traingle image here so when we move from y1 to y2 the value of x coordinate is changed to x2 which is greater than x1 but when i used the above formula to find value of x2 its giving me a value which is less than x1.

Why its so?

devpa
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  • "when i used the above formula to find value of x2 its giving me a value which is less than x1" -- I don't believe it. Show your work so someone can tell you your mistake. – David K Apr 01 '19 at 03:43
  • Let slope =1.73 Let x1=100 y1=100 y2=99 x2 = (x1-(y1-y2)/slope) = 100-(1/1.73) = 99.4219 x2 is less than x1 it must be greater according to fig link – devpa Apr 01 '19 at 03:59
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    @David I found my mistake. – devpa Apr 01 '19 at 04:57

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