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I think my question is how can I calculate N(-d1) if I know N(d1)? I got a question (with solution):

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So I know how to calculate the value of the call, but how should I get the value of N(-d1) or N(-d2) given the value of N(d1) or N(d2)?

Betty
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  • Why do you need $N(-d_1)$? For a European put you can just get the call price and then use Put Call Parity. – lulu Apr 13 '19 at 20:22
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    Standard normal distribution is symmetric so $N(x)+N(-x)=1$. – p.s. Apr 13 '19 at 20:24

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