What b and c should equal to, to say that this equation is correct(the base of log is 2): $$ N^b (\log N)^c = 2^N $$ *I'm a beginner in Math and need this to be done to go further. Would be nice if you gave me some explanation or links to articles to read
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@JimmyR. The base is 2 – Roman Roman Apr 16 '19 at 11:08
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$N=4$, $b=1$, $c=2$ is a solution – J. W. Tanner Apr 16 '19 at 11:16
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I'm not sure this has a solution, if you mean ''for all $N$, ...'' – Trebor Apr 16 '19 at 11:22
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$N=16, b=2, c=4$ is another solution – J. W. Tanner Apr 16 '19 at 11:39
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There are infinite possible solutions for many but not all positive real number values of N. – jvm Apr 16 '19 at 12:08
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It's never true for $N=1$. – Robert Israel Apr 16 '19 at 12:46