Can we say that $\log _4 (n^2)=\log _2(n)$? If that is the case, then $\displaystyle 2^{\log _4 (n^2)}=n$? Thanks.
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Yes. Let $x=\log_4n^2=2\log_4n$; then $2^x=2^{2\log_4n}=\left(2^2\right)^{\log_4n}=4^{\log_4n}=n$.
Brian M. Scott
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@bigO: You’re welcome. – Brian M. Scott Mar 03 '13 at 15:24