0

enter image description here

Ok I Get everything up until the point where it says. k $\sqrt{k+1}$ + $\sqrt{k+1}$ = (k+1) $\sqrt{k+1}$ How in the world did they get there? Or am I missing something else

Dani Jo
  • 93

1 Answers1

2

Just factor out a $\sqrt{k+1}$ from the left hand side. This yields $(k+1)\sqrt{k+1}$ which is what they claim.

Randall
  • 18,542
  • 2
  • 24
  • 47