Find the ratio between the radii lengths of the circumcircle and the inscribed circle of a triangle I have tried using the rule: $$\frac{a}{\sin{A}}=\frac{b}{\sin{B}}=\frac{c}{\sin{C}}=2R$$ Where R is the radius length of the circumcircle but i did not get the asnwer
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Possible duplicate of Relation between circum radius, inradius and the angles. – YuiTo Cheng Apr 23 '19 at 15:57
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Hint: $\verb/Area/ = \frac12 ab \sin C = \frac12 r(a+b+c)$ – achille hui Apr 23 '19 at 16:13