Studying Lebesgue Integration and have come across the following function on Wikipedia: $$f(x)=\frac{1}{x}\sin\left(\frac{1}{x^3}\right)$$ I was wondering why the above function is not Lebesgue integrable? And why is it Gauge integrable?
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1What do you mean by "Gauge integrable"? – uniquesolution Apr 25 '19 at 12:12
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@uniquesolution the Gauge Integral is a very well-known concept. – Umberto P. Apr 25 '19 at 12:23