Let $f:[a,b]\to \mathbb{R}$ be a smooth positive function and let $\Omega = \{(x,y)\in\mathbb{R}^2\big|x\in[a,b],0\le y\le f(x)\}$. Consider a smooth function $F:\mathbb{R}^2\to\mathbb{R}^2$. Use integration by parts to show that $$\int_{\Omega}\nabla\cdot Fd\mathbf{x}=\int_{\partial\Omega}F(s)\cdot\mathbf{n}(s)ds$$
I know that on left hand: $$\int_{\Omega}\nabla\cdot Fd\mathbf{x} = \int_{\Omega}(\frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y})dxdy$$ And $$\int_{\Omega}\frac{\partial F_2}{\partial y}dxdy=\int_a^b\int_0^{f(x)}\frac{\partial F_2}{\partial y}dydx = \int_a^b(F_2(x,f(x))-F_2(x,0))dx$$ And I want to do the same to $\int_{\Omega}\frac{\partial F_1}{\partial x}dxdy$, but I just don't know how to take care of the boundary term on the integral. Any idea?