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In the given figure $TP$ and $TS$ are tangents to the given circle $r$ is point of circumference

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im trying but i could't find any idea and i forget my geometry knowledge please can some help this problem

thank you so much

SURYA
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1 Answers1

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$\angle PRS = \angle TPS $ by inscribed angle theorem

$\angle TPS = \angle TQP$ by your definition of $Q$

So, we have $\angle PRS = \angle TQP$ and that means that $TQ||SR$ (corresponding angles)

To prove 7.2 note that $\angle TSP = \angle TPS = \angle TQP$ and so TPQS is inscribed (it is equivalent to $\angle TSP = \angle TQP$)

To prove 7.3 note that we know that TPQS is inscribed, so $\angle TPS = \angle TQS$ (by inscribed angle theorem)

kvardekkvar
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