Eliminating parameter

Asked May 01 '19 at 19:34

Active May 01 '19 at 19:44

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How do you solve for "$t$" in either equation to eliminate the parameter and solve in terms of $x$ and $y$? $$ \begin{split} x&=\frac{ 1+t }{ \sqrt{1+t^2}}\\ \\ y &= \frac{1-t}{\sqrt{1+t^2}} \end{split} $$

edited May 01 '19 at 19:44

Daniele Tampieri

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asked May 01 '19 at 19:34

Jared

1

$x+y = \frac{2}{\sqrt{\cdots}}, x - y = \frac{2t}{\sqrt{\cdots}} \implies t = \frac{x-y}{x+y}$ – achille hui May 01 '19 at 19:39
Typesetting hint: try enclosing the inside of your square root in braces: $\sqrt{ ... }$ – Théophile May 01 '19 at 19:43

Eliminating parameter

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