A Straight line is added to y=ln(2x+7) to obtain a solution of e^4x(2x+7)-e^9=0. Determine the equation of the straight line. Please help
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what have you tried? – Saketh Malyala May 02 '19 at 16:04
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Finding the asymptote of y=ln(2x+y). X=-3 – Cate May 02 '19 at 16:07
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I can’t seem to solve the second equation. Are we supposed to? – Cate May 02 '19 at 16:10
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Please help..I can’t understand – Cate May 03 '19 at 01:51
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$$e^{4x}(2x+7)=e^9 \ \iff \ e^{4x-9}(2x+7)=1$$
Take the natural logarithm of LHS and RHS :
$$(4x-9)+\text{ln}(2x+7)=0$$
Is $y=4x-9$ what you call the "straight line" to be added ?
Jean Marie
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The way you have asked the question, this "looks" to be the solution... – Jean Marie May 03 '19 at 04:59
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Besides, I have had a look at questions you have asked in the past : please chek answers that are satisfying for you. Doing that helps future readers to know that a certain answer is the good one. – Jean Marie May 03 '19 at 05:04