comparing area of a square with area of rectangle

Question

If we have a geometric sequence we have $a_1, a_1*r, a_2*r$

So $b=a_1*r$ and $c=a_2*r$

The square has area $b^2$ which is $(a_1*r)^2$ and the rectangle has area $ac = a_1*a_2*r$

I don't know which one is bigger or if this was even a correct way of interpreting the problem. Can someone please help.

$a_2=b=a_1r$. So, $c=a_2r=a_1r^2$. – CY Aries May 08 '19 at 01:46 — CY Aries, May 08 '19 at 01:46

score 1 · Accepted Answer · answered May 08 '19 at 01:45

1

$a$, $b$ and $c$ is in a geometric sequence.

$\dfrac{b}{a}=\dfrac{c}{b}$

So, $ac=b^2$.

answered May 08 '19 at 01:45

CY Aries

ugh i am so dumb, thanks for the help. – user130306 May 08 '19 at 01:46
i can accept your answer in 11 min, so i'll do it then – user130306 May 08 '19 at 01:46

1 Answers1