I am trying to understand the solution of this problem . I am unable to understand why :
If $yx=x^2y$, then $yxy^{-1}=x^2$. This means that $y^3xy^{-3}=x^8 $
It seems like I am missing something silly , but why is this true ?
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John
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1@Alvin Lepik No, this is not true. We do not suppose that the group is abelian. This is what we need to prove. – Mark May 18 '19 at 15:38
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$(ab)^c = (ab)(ab) \cdots (ab) $ Then , why is it so , @Alvin Lepik – John May 18 '19 at 15:39
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@Mark , if we raise to power 3 we get : $y x^3 y^{-1} = x^6 $ but then what ? – John May 18 '19 at 15:40
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1My comment was wrong. I deleted it. – Mark May 18 '19 at 15:41
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1Ditto what Mark said. – AlvinL May 18 '19 at 15:47
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After you ask a question here, if you get an acceptable answer, you should "accept" the answer by clicking the check mark $\checkmark$ next to it. This scores points for you and for the person who answered your question. You can find out more about accepting answers here: How do I accept an answer?, Why should we accept answers?, What should I do if someone answers my question?. – Shaun May 18 '19 at 15:56
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1@Shaun , IThanks for reminding ! I wanted to accept it immediately but the website told me to wait 4 minutes , after which I forgot to mark it as the answer Lol :P – John May 18 '19 at 15:58
