How would I rearrange this formula?

Question

I have a project that I need an equation for, and it looks like this:

$$W = \frac{V}{0.15} \times V$$

I need to rearrange the equation, so that V is the subject. So, in this situation here:

$$\frac{V}{0.15} \times V = 106.666667$$

I would plug $106,666667$ into $W$ and get $4$ ($V$) as the answer.

I’m not very experienced in math, could someone help out? Thanks!

Welcome to MSE. Please use MathJax for formatting expressions. I've edited your post to improve the formatting. — 雨が好きな人, May 22 '19 at 10:34
Welcome to Mathematics Stack Exchange! A quick tour will enhance your experience. Here are helpful tips to write a good question and write a good answer. For equations, please use MathJax. — dantopa, May 22 '19 at 22:11

score 3 · Accepted Answer · answered May 22 '19 at 10:41

3

$W=\frac{V}{0.15} \times V$

$W= \frac{V^2}{0.15}\Rightarrow V^2=0.15\times W$

$V= \pm \sqrt{0.15\times W}$

Plugging your values

$V = \pm\sqrt{0.15\times106666667}$ $V= \pm\sqrt{16000000.05}$

$\therefore \boxed{V = \pm4000.000}$

answered May 22 '19 at 10:41

Vineet

auscrypt · Answer 2 · 2019-05-22T10:42:09.247

1

To obtain $V$ as the subject, you have $W = \frac{V^2}{0.15}$ which gives $V^2 = \frac{W}{0.15}$ and finally $V = \pm \sqrt{\frac{W}{0.15}}$.

edited May 22 '19 at 10:42

answered May 22 '19 at 10:40

auscrypt

It must be $$V=\pm\sqrt{\frac{W}{0.15}}$$ – Dr. Sonnhard Graubner May 22 '19 at 10:41
@Dr.SonnhardGraubner Ah, you're right, my mistake. I've edited the answer. – auscrypt May 22 '19 at 10:42

score 0 · Answer 3 · answered May 22 '19 at 10:49

0

I would write $$V=\pm\frac{\sqrt{15W}}{10}$$

answered May 22 '19 at 10:49

3 Answers3