what's the $\frac{\partial^2{f}}{\partial{x^2}}$ of this?

Question

$$f(x,y)=\ln(x^2+y^2)$$ I just need the final answer, I have done it and I want to make sure that if I did it correctly. Thanks.

For this and future similar problems, you can use symbolic differentiation online — avs, May 31 '19 at 04:41

score 3 · Accepted Answer · answered May 31 '19 at 04:32

3

$$\frac{\partial^2{f}}{\partial{x^2}}=\frac{2y^2-2x^2}{(x^2+y^2)^2}$$

answered May 31 '19 at 04:32

score 2 · Answer 2 · answered May 31 '19 at 04:31

2

$2\frac{(y^2-x^2)}{(x^2+y^2)^2}$

answered May 31 '19 at 04:31

19aksh

auscrypt · Answer 3 · 2019-05-31T04:35:21.677

1

The final answer should be $\frac{2(y^2-x^2)}{(x^2+y^2)^2}$.

edited May 31 '19 at 04:35

answered May 31 '19 at 04:30

auscrypt

There should be square of denominator..as per the quotient rule of differentiation – Vedant Chourey May 31 '19 at 04:33
@auscrypt, the denominator should have $(x^2+y^2)^2$, (I didn't downvote) – 19aksh May 31 '19 at 04:33

3 Answers3