$$A=\begin{bmatrix} 0.5 & 0.5 & & & & \\ & 0.5 & 0.5& & & \\ & & \ddots & \ddots & \\ & & & \ddots & 0.5\\ 0.5 & & & &0.5\\ \end{bmatrix}$$ I need to calculate the first and second singular values, and I know the first is $1$, please tell me how to get the second.
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This might be mosquitoes with canons, but your matrix is circulant. – Arthur May 31 '19 at 11:33
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I find a way just use power method, this matrix is good. But I can't get a generous answer with $n$. – ALEX May 31 '19 at 11:44
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@Arthur I did it with circulant. Thanks. – ALEX May 31 '19 at 11:57