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If the radius of an inscribed circle in a right triangle is $3 cm$ and the non-hypotenuse side is $14cm$, calculate triangle's area. I've tried to use the formula: $r= \frac{a+b-c}{2}$ but that doesn't help me that much.

Vuk Marković
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  • You know $r$ and $a$, so that is one equation between $b$ and $c$. Find another equation linking $b$ and $c$. – Empy2 Jun 01 '19 at 06:41

1 Answers1

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$3=\dfrac{a+14-c}{2}$ $\implies$ $c-a=8$

$a^2+14^2=c^2$ $\implies$ $(c-a)(c+a)=196$

So, $c+a=24.5$ and hence $a=8.25$

$A=\frac12 ab=57.75$.

CY Aries
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