I would like to integrate this $$\int x \ln x\sin x\mathrm dx$$
can I do it with another quick method than using integration by part?
I would like to integrate this $$\int x \ln x\sin x\mathrm dx$$
can I do it with another quick method than using integration by part?
Here is a fun but not very useful trick: if you know the antiderivative already, any integral can be computed using only $u$-substitution. Proof:
$$\int f(x) \, dx$$ Let $F'(x) = f(x)$. $$u = F(x), du = f(x) \, dx$$ $$\int du = u + C = F(x) + C.$$
So for your integral, we see that it can be solved using the magic $u$-substitution
$$u = -Si(x) + \sin x + \ln x (\sin x - x \cos x).$$
We have
$$du = x \ln x \sin x \, dx$$ $$\int du = u + C = -Si(x) + \sin x + \ln x (\sin x - x \cos x),$$
as desired.