The above equation is from this paper:
It has a min/a,b , which I don't understand. It is not the argmin, right?
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It means take the $\min$ over all values of $a,b$. – copper.hat Jun 03 '19 at 18:51
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2This means that $J(\alpha)$ is is the minimum value obtained of the expression $J(\alpha,a,b)$ after plugging in all values of $a$ and $b$ possible. – Vizag Jun 03 '19 at 18:51
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1It is the minimal value of $J(\alpha, a, b)$ where $\alpha$ is chosen beforehand and then we look at the values for all pairs $(a,b)$ and pick the minimal value – B.Swan Jun 03 '19 at 18:51