I'm not really sure how to approach this problem, but since I have two sides and an angle maybe I could use area=$\frac{absin(C)}{2}$. What would be the best way to approach this problem?
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1use law of cosines to find the third side – Vasili Jun 14 '19 at 01:22
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But then wouldn't that be assuming that the angle between those two sides is 30 degrees? – Jaemin Kim Jun 14 '19 at 01:24
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1"two sides containing it" - doesn't it mean that it's the angle between those sides? – Vasili Jun 14 '19 at 01:49
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Oh yeah I didn't read the question that way. Thank you. – Jaemin Kim Jun 14 '19 at 01:50
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1After you find the third side, divide double the area by the largest side to find the shortest altitude. – Vasili Jun 14 '19 at 01:56
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$8 \sqrt 3$ must be the longest side, so the shortest altitude would be the height corresponding to that side
so $$ \frac 12 (8\sqrt 3) h = \frac{6(8\sqrt 3)\sin(30)}{2} $$
which gives $h=3$
WW1
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