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The situation: $$x=\frac ab\quad \& \quad y=\frac a{b+c}$$

(Image here, won't allow me to post images because of my low reputation)

lulu
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Raylight
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  • If $x=a/b$ and $y=a/(b+c)$, then what? – Wuestenfux Jun 16 '19 at 14:12
  • Well, obviously $\frac 1y=\frac 1x+\frac ca$, at least when $a\neq 0$. Did you have something else in mind? – lulu Jun 16 '19 at 14:17
  • Can you clarify your question? As it stands, I have no idea what you are asking. You tag to "proof verification" which would suggest that you have a proof you would like verified....yet no proof (nor even statement) appears in the post. – lulu Jun 16 '19 at 14:37

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No, there isn't.

As $x=\frac{a}{b}$, we get $a=bx$. So, we have - \begin{align} y&=\frac{bx}{b+c}\\ &=\frac{x}{1+\frac{c}{b}}\\ &=\frac{x}{1+k}\\ \end{align} for $k=\frac{c}{b}$.

Thus, the relation between $x$ and $y$ always depends at least on one constant.

Ishan Deo
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