@user10354138, the question is different but yes it is related to the question you referred.
– Tushar Jun 21 '19 at 12:14
I'd say that L4 is executed at most (number of mantissa bits) times, hence the erros accumulated in summing up $y$ are up to that times $\epsilon$, so e.g. with IEEE doubles, the relative error is $<52\cdot 2^{-52}\approx 1.2\cdot 10^{-14}$
– Hagen von EitzenJun 21 '19 at 12:22