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The first question asks for positive integer solutions to $x\cdot y \cdot z=5^9$.

I solved it by finding the coefficient of $x^9$ of the generating function $(1 + x^1 + x^2 + x^3 ... + x^9)^3$ since $5$ is a prime.

which gives the answer $28$

But the second question which asks for positive integer solutions to $x \cdot y\cdot z=12^5$

where 12 is not a prime.

Not sure my solving step is correct or not.

If it is not wrong then how do I deal the situation like the second question?

Any assistance will be appreciated. Thanks

Tverous
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1 Answers1

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Write $12^5=2^{10}3^5$ and consider the two equations $xyz=2^{10}$ and $xyz=3^5$ using the method you used for the first question. The number of solutions to the original second question is the product of the numbers of solutions to these two sub-questions: $\binom{12}2\binom72=1386$.

Tverous
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Parcly Taxel
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  • Thanks for the help. – Tverous Jun 29 '19 at 07:17
  • @"Parcly Taxel", thanks to the help from @"Henno Brandsma"'s comments above. I realized that $x^0$ is acceptable for the generating function. So the answer should remain the same. Which means the answer you wrote in the first place, $\binom{12}2\binom{7}2$ ,is correct. Sorry. – Tverous Jun 29 '19 at 10:35