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I am trying to find the range of: $\Large\frac{4 - {\frac {4 + a^2}{a}}}{\frac {1}{2} - \frac {1}{a}}$

So, we have: $a \ne 0$

$\frac {1}{2} - \frac {1}{a} \ne 0 $, $-\frac {1}{a} \ne -\frac {1}{2}$, $\frac {1}{a} \ne \frac {1}{2}$

I am not sure how to solve the last inequality. Thank you in advance!

Valeri
  • 167

2 Answers2

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Simplify it and you get $-2(a-2)=4-2a$. With $a \neq 0 \implies 4-2a \neq 4$, and for $a \neq 2 \implies 4-2a \neq 0$. Thus the range is $(-\infty, 0)\cup (0,4)\cup (4,\infty)$.

DeepSea
  • 77,651
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It is equivalent to $$\frac{-\frac{(a-2)^2}{a}}{\frac{a-2}{2a}}$$